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TODAY's MATH QUESTION

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Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 07:59
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Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 08:14
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WAIT... I'm writing a program to figure this out.
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 08:40
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B. two
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 08:41
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Originally posted by Bigdaddy0381 Bigdaddy0381 wrote:

B. two

good in math bad in grammar!!

c. is two b. is oneLaugh
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 08:43
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Two looks correct when you look at the x axis.
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 08:45
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I"ll say "D" for 3.
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 08:53
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BD, explain how you arrived at 2...
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 09:15
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i really sucked at math so i will take my usual guess of zero
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 09:22
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I would have to say A. or just line up where the x and y axis intersect right behind the front shoulder and squeeze the trigger.
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 14:50
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This makes my wittle head hurt.
D=3

Edited by BeltFed - February/10/2010 at 14:54
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 15:24
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I'll Pass.

Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 15:43
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C. 2) The first between -1 and 0 and the second between 6.5 and 8. Not enough lines on the graph to be more accurate than that..........
 
 
...........I think


Edited by Chris Farris II - February/10/2010 at 15:45
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 16:17
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he is not asking where the function crosses the x axis. g(x)=f(x) except being displaced left or right by some constant.
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 16:23
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Originally posted by Dale Clifford Dale Clifford wrote:

he is not asking where the function crosses the x axis. g(x)=f(x) except being displaced left or right by some constant.
I think that is what it is asking considering it says nothing about the change of y from f to g. Therefore we have no idea where the g will cross the y axis on the graph so all we do know is how many times it will cross the x axis between -5 and 15 which is 2. If I am  wrong please explain. Not to insult your itelligence Dale I know you are a very wise man I am just trying to understand if I am wrong and explain where I am coming from to you that is all.
Hiding


Edited by Chris Farris II - February/10/2010 at 16:35
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 16:25
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Get Your Popcorn Ready
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 16:38
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the "picture" (graph)  is of f(x), the "picture" (graph) of g(x) would be 4 units to the left going through the orgin.
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 16:44
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Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 16:49
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Originally posted by Dale Clifford Dale Clifford wrote:

the "picture" (graph)  is of f(x), the "picture" (graph) of g(x) would be 4 units to the left going through the orgin.
CFII Whacker Dale
 
You're exactly right I left out the fact that it would mean you have to have g(x) -4, becasue g(x)= f(x)+4 the way I was doing it would be g(x)=f(x)-4. Am I understanding now?
 
 
The answer is still 2 though... lol


Edited by Chris Farris II - February/10/2010 at 16:51
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 17:14
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Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 17:43
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g(x)=0 where f(x)+4=0. Look at the graph and think about it.

Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 19:34
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expand x in f and g
f(x)=x*3+15x*2-16x-240
g(x)=x*3*3x*2-88x
find roots with TOL set to 10*-11
g(x)=6.3x10*-6
f(x)=4 of course


Edited by Dale Clifford - February/10/2010 at 19:37
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-4 
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 21:53
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I would say c two by the fact that the graph of g(x) is just 4 units shifted up form f(x). It is not a horizontal shift because a horizontal shift effects the inputs not the outputs. A horizontal shift would be of the form g(x)=f(x+4) for example. Thus I think that the difference between f(x) and g(x) is the graph of g(x) is shifted vertically up 4 units...Am I right?
Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 21:59
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Post Options Post Options   Thanks (0) Thanks(0)     Back to Top Direct Link To This Post Posted: February/10/2010 at 22:02
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Simplicity it the best course... don't make the problem more difficult than it is.  You are merely looking at the result of graphing a function, then visualizing the result of translating that function...

The graph of the function g(x) is the same as the graph of the function f(x) translated UP 4 units.  f intersects the x-axis three times, but if the graph is shifted UP 4 units, the graph can only intersect the x-axis twice. g(x) is equal to zero for exactly two values of x between -5 and 15...

You let me fool you, it is a matter of inspection only...
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