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MOA/MOA or MIL/MIL |
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Easy2
Optics GrassHopper Joined: April/11/2009 Status: Offline Points: 7 |
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I am a lost here, if my windage says 2.5 moa I dial 2.5 moa, there is no math?
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Easy2
Optics GrassHopper Joined: April/11/2009 Status: Offline Points: 7 |
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Jon A
Optics Journeyman Joined: March/14/2008 Location: Everett, WA Status: Offline Points: 670 |
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In the interest of saving space and being simple, many or even most simple drop charts people make list only the 10 MPH wind value. So the chart says 2.5 MOA for 10 MPH wind.
So if the wind is only blowing 7 MPH, how much do you dial? |
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338LAPUASLAP
Optics Master Scope Swapper Joined: October/17/2009 Status: Offline Points: 2596 |
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After the PM's here is my explanation at the bottom.
The cover up of Dots is an entire other debate or explanation but mils vs MOA is easy IMO. Skip next paragraph I misinterpreted the question. What is the temp, humidity and what is the altitude, barometric pressure, angle of wind, bullet weight, velocity, range? = 62.832/60 = 1 min so 1 min = 1.0472~ Wind drift (in MOA / INCH = 12 x (88 x s /60) x sin a x (t - (3 x r) / v) NO CHART is going to do it for you or no scope that I know of regardless of reticle math is necessary. Not able to do math not able to hit 1st time... No rock or ground shooting... Mil = miliradian. A radian is approx. 57.295645 degrees, or there are 6.2832 radians in a circle. This makes 6283.2 miliradians in a circle and makes 3.438 moa in a mil. this is often rounded to 3.44 and we use 3.5 for ease of math. With our math this would make 35 inches at 1000 yards in stead of 36 inches. Mils can range a target by using is height in meters X 1000 / mil height. METERS Can MOA do this? Is it not the most important thing of shooting a target? Knowing its (target or animal) approx. distance. Conversion of mm to inches? 3.1416
x 2 equals 6.2832 (number of radians in a circle) with 360 divided by 6.2832
equals 57.295645 degrees. A miliradian is 1000th of that or 6283.2 in a circle.
Thus 1 mil equals 21600 (number of moa in a circle) divided by 6283.2 equals
3.4377387 or 3.438 moa in a mil. Or 100 x 2 x 3.1416 – 628.32 yrds then 628.32
x 36 – 22619.52 inches 22619.52 / 360 – 1 degree 1 degree = 62.832 inches – 62.832
/ 60 – 1 minute 1 minute – 1.0472 or =100*2*3.1416*36/360/60=1.0472 1 Milliradian = 1/1000th of a radian, 1 radian = 2 PI 1 Milliradian = .0573 degrees or 6283 parts of a circle USAR:
360 degrees = 1 circle
USMC:
360 degrees = 1 circle USAR:
3.375 moa X 1.047” = 3.533625” @ 100yrds or 35.33625” @ 1000yrds Since a radian is approx. 57.295645 degrees, or there are 6.2832 radians in a circle. This makes 6283.2 miliradians in a circle and makes 3.438 moa in a mil. this is often rounded to 3.44 and we use 3.5 for ease of math. With our math this would make 35 inches at 1000 yards in stead of 36 inches.
MIL/MIL Original Question... For hunting and long range target shooting, would the
MIL/MIL system or MOA/MOA system be more beneficial. I will typically be
dialing for elevation and holding for wind.
I haven't had much trouble with a MIL reticle/ MOA turrets
either, but it just makes plain sense to match them up. Sighting in is
quick and easy, and one less column on the dope chart. 1/8 is very nice for precise MIL is nice for ease. MIL DOTS/CIRCLES/OVALS are another subject that gets me goin |
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No one
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jonoMT
Optics Master Extraordinaire Joined: November/13/2008 Location: Montana Status: Offline Points: 4853 |
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Multiplying .7 * 2.5 = 1.75 MOA. Of course, looking for the easier math, I thought "25 * 7 = 175" then divided that by 100. You'll be close enough at a fair ways, but if you run your load(s) through JBM, you'll see that the results vary more as you get out there. |
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Reaction time is a factor...
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Jon A
Optics Journeyman Joined: March/14/2008 Location: Everett, WA Status: Offline Points: 670 |
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Correct. But most everybody will be faster answering 7 times 7 and less likely to make a mistake. .7 * .7 = .49 Mils. Easy.
You're missing the point. All that math is done when you make up the chart. Everybody realizes that at extreme ranges a simple chart doesn't do the job and individual solutions with real-time weather input is required. This is a small percentage of most people's shooting. Any time your 10 MPH wind correction is only .7 mils, you are close enough a chart does just fine and changes in the weather won't affect the answer enough to worry about (they'll be smaller than your ability to judge the wind is accurate). |
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Easy2
Optics GrassHopper Joined: April/11/2009 Status: Offline Points: 7 |
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I follow you now. I miss understood the question. Yes , you are right the math is easier for the
wind correction from that standpoint. But not overly difficult to do in moa.
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